javascript - CSS selector combine with And operation '&&' -

I'm trying to use querySelectorAll () to get each 'td' element in which the alignment attribute is & Amp; The child of 'tr' is

This works:

  document.querySelectorAll ('tr & gt; td');  

And it works:

  document.querySelectorAll ('[align]');  

But how to combine them?

Preface: None tr & gt; Point to td in front of:. That's why I left it down.

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It depends on what you want to do.

1. If you only align attribute with td element attribute:

     document. QuerySelectorAll ("td [align]")  

2. or only td element which are tr elements whose Close a align attribute

     document. The class selector is the only element < td  
    
    or  alignment  attribute containing the attribute ("tr [align] gt; td")  

   / Code> elements children

     document.querySelectorAll ("td [align]")  

3. < > Document.querySelectorAll ("td [align]")

... and so on; .

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Enter your comment below:

It works, but is there a way to not select TD before every t?

There is nothing about this in your question.

You can use td: not (: nth-child (0)) means "a td means that the first child of her parents " provided" is not that you have script code> tr (which is valid, but It's a strange thing.) With that rule, it works, because only td and scripts are valid codecs tr .

Or you just select pants and all relevant td s and then:

  var list = Array.protot Ype.slice.call (document.querySelector ("whatever"), 1);  

... the first entry in the list returned by you querySelectorAll .

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Further comment:

tr [style]> gt; td [align]: not (: nth -child (0)) 550 node list returned is equal to tr [style]> td [align]

right. Again, : nth-child sees who this child is, no where it comes in the list selected by the previous selector.

If you want to leave td first in the Each line, and you want to ignore tr with which is not a style attribute, it is more complex:

  var results = Array.prototype.reduce.call (document.querySelectorAll ("tr [genre]") , Function (list, line) {list.push .color (list, array.propytipicolicycol (line.quiricious all ("tr [align]"), 1)); return list;}, []);