Wednesday, 15 February 2012

Unable To Access PHP Global Variable -


I'm trying to drag global variable $ nsfw but it does not show anything. If I resonate it inside the function, then it works. But outside, it fails even when it is defined in the global form. Please help me here.

  & lt ;? Php if (! Function_exists ('do_example_work')) {function do_example_work () {global $ nsfw; ("Include / dbconnect.php"); // Create Connection $ conn = new mysqli ($ DBHOST, $ DBUSER, $ DBPASS, $ DBNAME); // Check connection if ($ conn- & gt; connect_error) {dead ("Connection failed:". $ Conn-> connect_error); } $ Sql ​​= "Select the field name from the table where '$' anything" "; $ result = $ conn- & gt; query ($ sql); ($ Row [" fieldname "] == 1) (If $ $ -> $ line = $ result-> output data of each row ($ result-> num_rows & gt; 0) / something $ nsfw = 25; out Go ();} and {resonate "joy";}}} {echo "0 result"}} echo $ nsfw;};? & Gt;  

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There are logic for globals and you can search the pile and the Internet and read about it:

  1. G Lobels are bad in many ways, and should be avoided where possible
  2. Globals are not bad and can be fine if you know what you are doing then safe to use /

manual:

function.

OUT

If you have data for a function Use statement

  function do_example_work () {// some stuff here, if you want to get  outside  $ Nsfw = 25; Return $ NSFW; // where required, conditional statement or the completion of the function} // "echo" resonates 25 i_example_work ();  

IN

FYI:

To get data out in , simply pass Make the data passed from your function as an argument from outside:

  function do_example_work ($ nsfw) {/ ** var "$ nsfw" through function call * Gone data can be used as required - $ nsfw == Check something * or this database can be login details (urgh) * / echo $ nsfw. "- and the word from the function"; } // Will "pass in logic" and "word from function" will be "do_example_work" (in the argument "pass");  

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