I am trying to get a simple problem in MySQL: the table I created by 3 fields And I want to have a field in the form of a query that gives the field selected as DISTINCT and two more columns, which corresponds to a specific situation, when one of the remaining two fields returns back.
For example ( ago , second and third left to right):
< Code> | WojokAAD | AAA | 0 | | VziAAAT | BBB | 0 | | VziAAAT | CCC | 1 | | VziAAAT | DDD | 0 | | W0cZAAT | I | 1 | | VziNAAT | FFF | 1 | | VzpqAAD | | Jig | 1 | | VzpqAAD | | HHH | 1 |
My existing query is structured as follows:
select field_one as the difference (first), second from the table (number) third = 0 group By field_one;
will return the above questions:
| WojokAAD | 1 | | VziAAAT | 2 |
I can change the query to do something like this:
SELECT DISTINCT (first) AS field_one, COUNT (seconds) WHERE third from the table = 1 GROUP by Field_on;
And it will return:
| VzpqAAD | | 2 | | VziNAAT | 1 | | W0cZAAT | 1 | | VziAAAT | 1 |
How can I get both questions together, so that I got the first column group and distint and got two extra columns, respectively, with the third = 1 and the third = 0 .
Actually something like this (wrong course):
select difference (first) AS field_one, COUNT (second WHERE third = 1) alpha, COUNT (second WHERE Third = 0) field beta on AS beta from table group;
I tried to use the CASE and IF control flow function though I managed to get results in only one column.
Thanks for giving thanks to someone
You just use this query First choose: First, choose SM (IF (third = 0,1,0)) as Col_one from group group Col_zero, SUM (IF (third = 1,1, 0));
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