Saturday, 15 August 2015

python - DJANGO celery task is executed from shell but it's not executed from view -


I'm trying to create some asynchronous tasks with celery in my own design app

settings .py

  BROKER_URL = 'Django: // local host: 6379/0' CELERY_ACCEPT_CONTENT = ['json'] CELERY_TASK_SERIALIZER = 'json' CELERY_RESULT_SERIALIZER = 'json'  

celery .py:

  django.conf import setting os.environ.setdefault ('DJANGO_SETTINGS_MODULE', 'provcon.settings') application = celery imported from celery __future__ import absolute_import from celery Import OS ('from provcon') app.config_from_object ('django.conf: from  
 : setting') app.au Todiscover_tasks (lambda: settings.INSTALLED_APPS)  

import absolute_import from the .celery import app in the form of project __init__py __future__ celery_app

tasks.py:

Proc_Carga @ Task () def carga_ftp (): tabla =

 __future__ import. Import import celery from imported imported from imported_task to absolute_import from import_task. From my thoughts call asynchronous tasks: 

  Task import carga_ftp @ login_required (LOGIN_URL = '/ login /') def archivoview (request): usuario = request.user if request.method == 'POST': form = ProcFTPForm (usuario, request.POST) If form.is_valid ( ): Form. Save () proc = Lista_Final () Lista = proc.archivos () # call asynchronous task carga_ftp.delay () return HttpResponseRedirect ( '/ resumen /') and: form = ProcFTPForm (usuario) return render_to_response ( 'archivo.html', {'Form': form}, context_instance = RequestContext (request))  

When I run a python with manage.py shell. The worker is executed and makes database objects without any problem

But when I try to execute the task sequence does not work

Any idea why the work

check whether the revision is going

 < code> $ redis-cli ping  

Check whether celery staff running Dijengo admin interface

If it The value is not executed

  Celery - A provoque worker - l info  

Check your work from your Dijengo app

If working, then the celery worker runs

as the background

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